8p^2+9p-6=0

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Solution for 8p^2+9p-6=0 equation: 



8p^2+9p-6=0

a = 8; b = 9; c = -6;
Δ = b2-4ac
Δ = 92-4·8·(-6)
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{273}}{2*8}=\frac{-9-\sqrt{273}}{16}
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{273}}{2*8}=\frac{-9+\sqrt{273}}{16}
$

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